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javedsk12 · Posted: Wed Feb 13, 2008 1:28 am Post subject: getting decimal values

hi frnds,

in my calaculator program which i am coding in cobol i have to calaulate

22/7 and user has the liberty to calcaulate the as many decimal points he wants as:

22/7 and if he spcified 3 so it should be 22/7=3.142 after decimal 3 digits if he is passing 10,20,30 so those no of digits should come after decimal point
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javed

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CraigG · Posted: Wed Feb 13, 2008 9:38 am Post subject:

Not a task for a beginner.

Mervyn · Posted: Wed Feb 13, 2008 9:39 am Post subject:

What's the question, anyway?
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cobcurious · Beginner Joined: 04 Oct 2003 Posts: 68 Topics: 25

Hi Javed,

Please note that there is an upper limit on the number of digits you can use in COBOL. I think it is 18 digits for a numeric number.

For customising the value of 22/7 ("pi"..I guess), you may have to use either variables of differing lengths. Also equal number of separate "result" variables (in which are going to put down the result of your calculations),depending on the number of digits selected after the decimal point for 22/7, to give you the precision in the result you are expecting.

Thanks
Tushar

Nic Clouston · Posted: Mon Feb 18, 2008 5:40 am Post subject:

I would say you only need one result variable in Packed Decimal format (COMP 3?? - my cobol ain't great) and a zoned decimal version which you can then etract the required length of answer from (after rounding) and a char field to isert the answer into (so that trailing zeros do not exist). Something along those lines anyway.
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