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Finding Leap year

 
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Rmravi
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Joined: 24 Jun 2004
Posts: 12
Topics: 5

PostPosted: Wed Sep 29, 2004 2:18 am    Post subject: Finding Leap year Reply with quote

How to find the leap year thru rexx is their any function available ?please help me in that

Ravi
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kolusu
Site Admin
Site Admin


Joined: 26 Nov 2002
Posts: 12376
Topics: 75
Location: San Jose

PostPosted: Wed Sep 29, 2004 5:47 am    Post subject: Reply with quote

rmravi,

try this

Code:

/* function checking for a leap year of an ISO date      */
isLeap: procedure
parse arg ISOdate

/* catch syntax error produced by wrong date value       */
signal on syntax
dummy = Date(, substr(ISOdate,1,4)'0229', 'Standard')
return 1           /* is valid date, --> leap year       */
syntax:
return 0           /* is invalid date, --> no leap year  */

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Kolusu
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Rmravi
Beginner


Joined: 24 Jun 2004
Posts: 12
Topics: 5

PostPosted: Wed Sep 29, 2004 6:51 am    Post subject: Reply with quote

Hi

I am new to rexx while running the peogram it saying the fllowing error could you pls guide me in that

LABEL syntax SPECIFIED BUT COMMAND NOT FOUND
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Rmravi
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Joined: 24 Jun 2004
Posts: 12
Topics: 5

PostPosted: Wed Sep 29, 2004 7:11 am    Post subject: Reply with quote

Sorry it is my mistake only Thanks Kolusu tahnks lot it is working fine
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superk
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Joined: 19 Dec 2002
Posts: 684
Topics: 5

PostPosted: Wed Sep 29, 2004 7:17 am    Post subject: Reply with quote

kolusu, that certainly makes sense as an algorithm. I always did it by making sure that the year was evenly divisible by 400, or by 4 and 100. I'll be adding this one to my REXX algorithm list.
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danm
Intermediate


Joined: 29 Jun 2004
Posts: 170
Topics: 73

PostPosted: Thu Oct 28, 2004 4:03 pm    Post subject: Reply with quote

Try this:
Code:

/* REXX _____________________________________________
| If 2 days between 3/1 and 2/28, it is a leap year. |
|__________________________________________________*/
Do I = 1990 to 2010
  If 2 = date('B',I'0301','S') - date('B',I'0228','S') then,
    say I 'is leap year'
  Else say I 'is not a leap year'
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